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3 years ago

Multiply using distributive property. (2x-5)(4x2-3x+1) PLEASE HELP!!! ASAP!!!

Mathematics

2 answers:

AysviL [449]3 years ago

7 0

Answer:

33x-6x(square)-45

Step-by-step explanation:

(2x-5)(9-3x)

= 2x(9-3x) + -5(9-3x)

= 18x-6x(square) - 45+15x

= 33x-6x(square)-45

Rama09 [41]3 years ago

3 0

Answer:

8x^3 - 26x^2 + 17x - 5.

Step-by-step explanation:

(2x - 5)(4x^2 - 3x + 1)

= (2x * 4x^2) + (-5 * 4x^2) + (2x * -3x) + (-5 * -3x) + (2x * 1) + (-5 * 1)

= 8x^3 + (-20x^2) + (-6x^2) + 15x + 2x - 5

= 8x^3 - 26x^2 + 17x - 5.

Hope this helps!

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Y-5 = -3 (x+2) in standard form

expeople1 [14]

Answer:

maybe y - -3x = -11?

Step-by-step explanation:

im rushing so i may have did it wrong sorry

8 0

3 years ago

The correlation coefficient r between the age of a homeowner, x, and the number of years remaining on the homeowner's mortgage,

marysya [2.9K]

Solution: We are given that the correlation coefficient between the age of a homeowner, x , and the number of years remaining on the homeowner's mortgage, y, is 0.485

We know that coefficient of determination is the percent of the variation in the dependent variable that is explained by the independent variable. The coefficient of determination is the square of correlation coefficient and is denoted by $R^{2}$

Therefore, we have:

$R^{2}= 0.485^{2}=0.235 or 23.5\%$ denotes

Hence the option 23.5% is correct

8 0

3 years ago

What would be the answer for this.

kvasek [131]

Answer & Step-by-step explanation:

We are given that m∠1 = m∠2. We are to prove that line l is parallel to line m. So, let's make a proof. Your first statement should always be the given statement. You are given the statements. All we have to do is find the reasons for those statements.

m∠1 = m∠2 → Given
m∠1 = m∠3 → Vertical angles are equal
m∠2 = m∠3 → Substitution
l ║m → If corresponding angles are equal, then lines are parallel

4 0

4 years ago

Jessica wants to buy a new team jacket that’s cost 35$

OlgaM077 [116]

She would spend $35.00 on each jacket. Just multiply

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3 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago