Pls give the question to expect that u get answers from others
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Answer:
<em>π/2 and π/3</em>
Step-by-step explanation:
Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.
let P = cosx
The equation becomes 2P²-P = 0
P(2P-1) = 0
P = 0 and 2P-1 = 0
P= 0 and P = 1/2
Since P = cosx
cosx = 0 and cos(x) = 1/2
If cos(x) = 0
x = cos⁻¹0
x = 90⁰
x = π/2
If cos(x) = 1/2
x = cos⁻¹1/2
x = 60⁰
x = π/3
<em>Hence the solutions to the equation are π/2 and π/3.</em>
Slope = (-6 - 3)/(1+2) = -9/3=-3
y - 3 = -3(x +2)
y - 3 = -3x - 6
3x + y = -3
answer is 3x + y = -3 (third one)
Ok. first you have to pick x or y or whatever variable you have and the number multiplied with it has to be the same in each equation but one has to be positive and one negative.
lets pick x
y=-2x+6
3y=x-3/ *2
so the x are positive and negative we have to multiply the equation with 2
y=-2x+6
6y=2x-6
now you have to add the equations. you do that by adding each side of the equatins together like this:
y+6y=-2x+6+2x-6 the x will cancel out
7y=0
y=0
now just go back to one of the previous equations and put the y in it.
0=-2x+6
2x=6
x=3
here you go
