Answer:
15°.
Step-by-step explanation:
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Have a good Day!
If and only if it is a proportional relationship, the problem can be solved by creating a proportion of B1/T1=B2/T2. This can also be expressed as 4.5/3.5=5.4/x given the values. You must cross multiply, so 4.5x=3.5(5.4). This simplifies to x=4.2. So, the tail length would be 4.2 feet.
Hope this helps.
In order to find the area for a strange shape, you divide it up into simpler figures. In this case, you already know that it can be divided into 4 triangles, so find the area of each triangle and add them up. Hope this helped!
Answer: If this isnt wrong then I probably forgot how to do this... You plug in 10 with 
10^2. so then you'll get 100 time pi and youll get 314.159265.
To do this we need to see how many degrees it dropped then divide by time (15 hr.).
52 - (-23)
75
75/15
5 deg/hr
Hope this helped!
