Let's start with m∠1. m∠1 <em>has </em>to be 90º because line segment AB is perpendicular with line segment AC, as it shows a right angle symbol on the angle beside m∠1. Now that we know that, it will be much easier to find m∠2 and m∠3 because m∠1, m∠2 and m∠3 are part of the triangle formed in the middle, and all angles in a triangle add up to 180º. 180-90 is 90, therefore, m∠2 +m∠3=90º so all three angles add up to 180º. You don't even have to find the specific angle measurements.
Hope this helps. I also attached a (rather poorly edited) image.
Answer:
t + 0.8 =1.5
Step-by-step explanation:
Our objective is to get to 1.5. we know that part of the distance is 0.8 but we don't know the other half (t).
Answer:
35 is the length of BE
Step-by-step explanation:
2(2x + 5) = 8x - 50
4x + 10 = 8x -50
10+50 = 8x-4x
60= 4x
15 = x
2x + 5 = length of BE equal to length of DE
2(15) +5 = BE
30 +5
35 is the length of BE
Answer:
-5y
Step-by-step explanation:
15 = 3×5
55 = 5×11
-15xyz = -1 × 3 × 5 × x × y × z
-55xy² = -1 × 5 × 11 × x × y²
-55yz = -1 × 5 × 11 × y × z
HCF = multiply all common factors with the lowest power amongst all 3 expressions
HCF = -1 × 5 × y = -5y
x=11.4242....
100x=1142.4242....
100x-x = 99x = 1131
x=1131/99 = 11 42/99 (unreduced) = 11 14/33 (reduced fraction)
