The fourth class ends at 12:30 pm
<em><u>Solution:</u></em>
Given that Harold has 4 classes each morning
Each class is 1 hour long, and there are 10 minutes between classes
The first class is at 8 A.M
<em><u>To find: Time at which fourth class ends</u></em>
Since each is 1 hour long and 10 minutes gap between classes
First class = 8 A.M to 9 A.M
Second class = 9:10 A.M to 10 : 10 AM
Third class = 10 : 20 AM to 11 : 20 AM
Fourth class = 11 : 30 AM to 12 : 30 PM
Thus the fourth class ends at 12:30 pm
I think (-6,-2) because it would switch into the all negative quadrant making them both negative.
Answer:
B. BD = 9
Step-by-step explanation:
Simply set the 2 equations equal to each other (both are congruent due to perpendicular bisector):
6x + 3 = 3x = 6
3x + 3 = 6
3x = 3
x = 1
Then substitute 1 for <em>x</em> in BD
6(1) + 3
6 + 3
BD = 9
