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Sedbober [7]
2 years ago
10

Asher opened a savings account by making an initial deposit and setting up weekly automatic deposits as shown in the graph. How

much was Asher's initial deposit?
what is the amount of Asher's weekly deposit?
write and equation to represent the situation?

Mathematics
2 answers:
vampirchik [111]2 years ago
8 0

Answer:

20 is the initial deposit and weekly deposit is $7.5

Sergio [31]2 years ago
5 0

Answer:

  • y = 7.5x + 20

Step-by-step explanation:

As per the graph, the y-intercept is 20 which is the initial amount.

Another marked point has coordinates (4, 50).

<u>The slope is:</u>

  • m = (50 - 20)/4 = 7.5

<u>The equation of the line is:</u>

  • y = 7.5x + 20

$20 is the initial deposit and weekly deposit is $7.5

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parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm. point F is on RS exactly 5 cm from S. let T be the intersection of PF
Doss [256]

<u>Solution-</u>

Given that,

In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.

Then considering ΔPQT and ΔSTF,

1-    ∠FTS ≅ ∠PTQ            ( ∵ These two are vertical angles)

2-   ∠TFS ≅ ∠TPQ            ( ∵ These two are alternate interior angles)

3-   ∠TSF ≅ ∠TQP            ( ∵ These two are also alternate interior angles)

<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>

∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS} =\frac{TP}{TF}

As QS = TQ + TS = 10 (given)

If TS is x, then TQ will be 10-x. Then putting these values in the equation

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS}

\Rightarrow \frac{8}{5} =\frac{10-x}{x}

\Rightarrow x=3.85

∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm




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