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Sedbober [7]
3 years ago
10

Asher opened a savings account by making an initial deposit and setting up weekly automatic deposits as shown in the graph. How

much was Asher's initial deposit?
what is the amount of Asher's weekly deposit?
write and equation to represent the situation?

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0

Answer:

20 is the initial deposit and weekly deposit is $7.5

Sergio [31]3 years ago
5 0

Answer:

  • y = 7.5x + 20

Step-by-step explanation:

As per the graph, the y-intercept is 20 which is the initial amount.

Another marked point has coordinates (4, 50).

<u>The slope is:</u>

  • m = (50 - 20)/4 = 7.5

<u>The equation of the line is:</u>

  • y = 7.5x + 20

$20 is the initial deposit and weekly deposit is $7.5

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givi [52]
C is 20 degrees. Pls mark brainliest
8 0
3 years ago
The formula v equals the square root of the quantity 64 multiplied by h end of quantity gives the velocity v in feet per second
NemiM [27]
The equation is derived from the conservation of energy, specifically from potential energy stored at a given height in a gravitational field.

When potential energy is completely converted to kinetic energy you have:

(mv^2)/2=mgh  divide both sides by the mass m

v^2/2=gh  multiply both sides by 2

v^2=2gh take the square root of both sides

v=√(2gh)  and working with imperial units for acceleration due to gravity, g=-32ft/s^2

v=√(-64h)  but the change of h as it falls is negative h so

v=-√(64h) so if an object falls from a height of 88ft we have:

v=-√(64*84)

v=-√5376

v≈-73.32 ft/sec (to the nearest hundredth of a foot per second)

Note that this is the velocity, it is negative 73.32 ft/sec.

The question inadvertently asked for velocity and provided answers for SPEED.  Velocity is a vector and has both magnitude and direction, whereas speed just has magnitude.

So its final speed is 73.32 ft/sec

So if they actually wanted velocity none of their answers is correct :P
5 0
3 years ago
Read 2 more answers
Can someone please help me
agasfer [191]

Answer:

See below

Step-by-step explanation:

If |x| < |y|   and both are negative the x will be  to the right of y on the number line.  The point x is loser to the zero on the number line. We can illustrate this by supposing x = -3 and y = -6.

|x| = 3 and |y| = 6  and 3 < 6  but -3 on the number line is higher ( to the right) of -6 and closer to the zero.


|-8 1/3| = 8 1/3

|7  2/3|  = 7 2/3

The absolute values of 8 1/3 > than absolute value of 7 2/3.  The point 7 2/3 is closer to the zero on a number line.

The absolute value of F is greater than absolute value of E so E is closer to the zero line than F.


6 0
3 years ago
Aggh please help with this
docker41 [41]
Sure ill help you what you need help with
6 0
3 years ago
Suppose the amount of sun block lotion in plastic bottles leaving a filling machine has a normal distribution. The bottles are l
Gnom [1K]

Question:

Suppose the amount of sun block lotion in plastic bottles leaving a filling machine has a normal distribution. The bottles are labeled 300 milliliters (ml) but the actual mean is 302 ml and the standard deviation is 2 ml. If you purchase a package of 6 bottles of lotion, what is closest to the probability that at least one bottle has a content of less than 300 ml?

Answer:

0.645314

Step-by-step explanation:

Given:

Mean, u = 302

Standard deviation \sigma = 2

n = 6

Let's first find P(X>300):

Z = \frac{X - u}{\sigma}

Z = \frac{300 - 302}{2}

Z = -1

Using the standard normal table,

NORMSDIST(-1) = 0.158655

Thus,

P(Z<-1) = 0.158655

Find the closest to the probability that at least one bottle has a content of less than 300 ml:

Given that 6 bottles were purchased & p = 0.158655

Find:

P(X≥1) = 1 – P(X<1) = 1 – P(X=0)

Use bimonial distribution:

P(X=x) = ^nC_x*p^x*(1 - p)^(^n^-^x^)

P(X=0) = ^6C_0* 0.158655^0*(1 - 0.158655)^(^6^-^0^)

P(X=0) = 1*1* 0.841345^6

P(X=0) = 0.354686

Therefore,

P(X≥1) = 1 – P(X<1) = 1 – P(X=0)

= 1 - 0.354686

= 0.645314

The closest to the probability that at least one bottle has a content of less than 300 ml is 0.645314

6 0
3 years ago
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