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2 years ago

5(x-4)+2x=14 help me find the answer x=?

Mathematics

2 answers:

erik [133]2 years ago

8 0

Answer:

x = - 6/7

Step-by-step explanation:

Distribute 5 (x - 4) first --> 5x - 20

Combine like-terms: <u>5x</u> - 20 + <u>2x </u>= 14 --> 7x - 20 = 14

Subtract 20 on both sides: 7x = -6

Divide both sides by 7: x = -6/7

Bond [772]2 years ago

4 0

Exact Form:
x = 34/7

Decimal Form:
x= 4. 857142

Mixed Number Form:
x= 4 6/7

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3 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

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2 years ago

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3 years ago

The distance that Scott walks is a function of the time he spends walking. Scott can walk 1 half

MaRussiya [10]

Step-by-step explanation:

It is given that,

The distance that Scott walks is a function of the time he spends walking. Scott can walk 1 half mile every 8 minutes.

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$\dfrac{0.5}{8}=\dfrac{y}{x}\\\\\dfrac{x}{y}=16\\\\y=\dfrac{x}{16}$

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