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3 years ago

1.9/10 times 3/6 then simplified

Mathematics

1 answer:

givi [52]3 years ago

8 0

1) 0.095
2)0.1875
3)0.3
4)0.21875
5)0.133
6)0.66
7) 0.6
8)0.375

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RT and UW are parallel lines

Veseljchak [2.6K]

Answer: ∡RSQ and ∡TSQ

Supplementary angles are angles that add up to 180 degrees. We can see in the picture that both angles are located on the same line, and no other angles are involved, so they must equal 180.

We can also use the process of elimination:

∡RSQ and ∡UVS are congruent because they are consecutive angles.

∡RSQ and ∡WVX are also congruent because they are alternate exterior angles.
∡RSQ and ∡TSV are also congruent because they are vertical angles.

5 0

8 months ago

The value of a collectible coin can be represented by the equation y = 2 x + 15, where x represents its age in years and y repre

Nuetrik [128]

Answer:

y = 53

Step-by-step explanation:

To get the answer, first put 19 in place of the x, and then times that iwth two, getting 38, you add that to 15. The answer is 53.

3 0

2 years ago

Read 2 more answers

Need help with 31 pleeeee<br>

shutvik [7]

Answer: 1 hour

Step-by-step explanation:

2 gallons in, 3 gallons out per minute

means 1 gallon lost per minute

60 gallons in the tank so it will take 60 minutes to drain it completely

answer=1hr

7 0

2 years ago

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How do you justify <br> 10 (y+5) = 10

Alexeev081 [22]

Want a word problem for it
if u do it's 10of y plus 5 is 10

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2 years ago

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Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

2 years ago