So, the perfect point for the bulb is at parabolic focus. Thankfully, parabolic equation is given in a standart form. So, the visual representation on the carthesian will be a parabola laying sideways facing to the right, with an extremum of (2; -3). Standart view is
![y^2 = 2px](https://tex.z-dn.net/?f=y%5E2%20%3D%202px)
. Then, focal parameter is
![p = 13](https://tex.z-dn.net/?f=p%20%3D%2013)
. Then, focus will be at (2+0.5p; -3) or (8,5; -3).
Answer:
part 1: first one: 7
Step-by-step explanation:
Answer:
- 5
- 15
Step-by-step explanation:
We assume your expressions are ...
4x^5 + 3x^2 + 24
23x^3 – 35x^15 + 45x^9
The exponents of the variable in the terms of the first expression are ...
5, 2, 0
The largest of these values is 5, so the first expression has degree 5.
__
The exponents of the variable in the terms of the second expression are ...
3, 15, 9
The largest of these values is 15, so the second expression has degree 15.
Answer:
there are infinitely many solutions
Step-by-step explanation:
The rated speed of the access point = 2 GB/sec.
The throughput is half the rated speed = 1 GB/sec.
1 GB/sec. = 1000 MB/sec.
Each person downloading is getting an average of 200 MB/sec.
<u>So, the number of people are using the internet at that moment = 1000/200 = 5 persons.</u>