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slamgirl [31]
4 years ago
10

(5, 3) and (8, -2) Write the standard form of the equation of the line that passes through the given points.

Mathematics
2 answers:
Firlakuza [10]4 years ago
8 0
Answer is given above

Lerok [7]4 years ago
3 0
Slope = (y2 - y1) / (x2 - x1)
(5,3)...x1 = 5 and y1 = 3
(8,-2)..x2 = 8 and y2 = -2
now we sub
slope = (-2 - 3) / (8 - 5) = -5 / 3

y = mx + b
slope(m) = -5/3
use either of ur points..(5,3)...x = 5 and y = 3
now we sub and find b, the y int
3 = -5/3(5) + b
3 = -25/3 + b
3 + 25/3 = b
9/3 + 25/3 = b
34/3 = b

ur equation is y = -5/3x + 34/3...but we need it in standard form

y = -5/3x + 34/3
5/3x + y = 34/3
5x + 3y = 34 <=== standard form
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borishaifa [10]
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9(xy)/x - 4xy/y = 8xy         =>       9y - 4x = 8xy, or 9y = 4x + 8xy = 4x(1+2y)

                                                                        then 9y = x [ 4(1+2y) ]
                                                                                     9y
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7 0
3 years ago
BRAINLIEST to wherever gets this correct ​
schepotkina [342]

Answer:

300\pi cubic feet

Step-by-step explanation:

Let r be the radius of cone and h be the height of cone.

Radius of cylinder=r

Height of cylinder=h

Volume of cone=100\pi ft^3

We have to find the volume of cylinder.

We know that

Volume of cone=\frac{1}{3}\pi r^2 h

100\pi=\frac{1}{3}\pi r^2 h

r^2 h=300

Volume of cylinder=\pi r^2 h

Using the formula

Volume of cylinder=\pi (300)=300\pi ft^3

Hence, the volume of cylinder=300\pi cubic feet

4 0
3 years ago
Q # 8 please solve the problem
iren [92.7K]
The answer is cylinder
7 0
3 years ago
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There is a line that includes the point (4, 1) and has a slope of 1/4. what is its equation in
Lelechka [254]

Answer:

y=1/4x

Step-by-step explanation:

y=mx+b

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so, y=1/4x+b

Now, look at our line's equation so far: . b is what we want, the 1/4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,1).

So, why not plug in for x the number 4 and for y the number 1? This will allow us to solve for b for the particular line that passes through the point you gave!.

(4,1). y=mx+b or 1=1/4 × 4+b, or solving for b: b=1-(1/4)(4). b=0.

y=1/4x+0

3 0
3 years ago
Can you solve this please ;)
AleksAgata [21]
C) X is greater than or equal to 0

(Domain is all the x-values the line goes through)

3 0
4 years ago
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