Butane undergoes combustion to produce carbon dioxide and water, expressed in the following reaction <span> C4H10 (g) + O2 (g) → 4CO2 (g) + 5H2O (g) . 1 mole of butane is to 4 moles of CO2. In this case, when 22.8 grams of butane or 0.393 moles of it, 69.18 grams of carbon dioxide is produced</span>
Answer:
Car B has a greater momentum than car A
Explanation:
Given data:
Mass of car A = 1200 Kg
speed of car A = 22 km/hr
Mass of car B = 1200 Kg
speed of car B = 25 Km/hr
Solution:
For car A:
p = mv
p = 1200 Kg × 22 km/hr
p = 26400 kg.km/hr
For car B:
p = mv
p = 1200 Kg × 25 km/hr
p = 30,000 kg.km/hr
To confirm the results of the same experiment to see if they are similar
Answer:
8.3ml
Explanation:
to get volume u have to divide 25g over the density, i rounded to the nearest tenth, if you don't want to then write out the full number with all the decimals