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3 years ago

Which compound does not form a precipitate when reacted with sodium hydroxide?

Chemistry

1 answer:

Alla [95]3 years ago

5 0

Answer:

NaNO₃

Explanation:

A precipitate is a compound or a salt formed from a precipitation reaction and does not dissolve in water and therefore will exist in solid state.

From the choices given precipitation reaction will occur between;

Fe(NO₃)₃(aq) + 3NaOH(aq) → Fe(OH)₃(s) + 3NaNO₃(aq)
Cu(NO₃)₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaNO₃(aq)
FeSO₄(aq) + 2NaOH(aq) → Fe(OH)₂(s) + Na₂SO₄(aq)

Fe(OH)₃, Cu(OH)₂, and Fe(OH)₂ are precipitates.

From the rules of solubility, hydroxides are insoluble except Ca(OH)₂ which is slightly soluble and hydroxides of ammonium and alkali metals.

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. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r

Tom [10]

Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

Explanation : Given,

Wavelength = $435.8nm=435.8\times 10^{-9}m$

conversion used : $1nm=10^{-9}m$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength = $435.8\times 10^{-9}m$

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}$

$E=4.56\times 10^{-19}J$

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

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3 years ago

Explain the factors that affect the separation of mixtures in amino acids

Elenna [48]

Consider you have a mixture of amino acids(contains all set of amino acids such as polar, non polar). Other than TLC, how are you supposed to separate a single amino acid from the mixture without loss of amino acid quantitatively.

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3 years ago

The compound sodium carbonate is a strong electrolyte. Write the reaction when solid sodium carbonate is put into water:

Ludmilka [50]

The compound sodium carbonate is a strong electrolyte because it completely dissociates when placed in water into its component ions. The equation of the reaction can be expressed as:

$Na_2CO_3_{(s)} ---> 2 Na^+_{(aq)} + CO_3^{(2+)}_{(aq)}$

The dissociation leads to the formation of sodium and carbonate ions with the latter held together by its internal covalent bond.

This is unlike weak electrolytes that do not dissociate completely in water or aqueous solutions. Only a small fraction of the solute exists as ions in the solution.

More on strong and weak electrolytes can be found here: brainly.com/question/3410548

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3 years ago

A dialysis unit requires 70000 mL of distilled water. How many gallons of water are needed? (1 gal = 4 qt)

Lady bird [3.3K]

Answer: 19.25 gallons

Explanation: 1 ml = 0.0011 quart

Given: 4 quarts = 1 gallon

Thus if 1 ml is equal to 0.0011 quart

70000 ml is equal to = $\frac{0.0011}{1}\times 70000=77quart$

Now if 4 quarts is equal to 1 gallon.

77 quarts is is equal to= $\frac{1}{4}\times 77=19.25gallons$

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3 years ago

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When you mixed 20 grams of magnesium and an excess of nitric acid, 1.7 grams of hydrogen was actually produced. What is the perc

Kitty [74]

Based on the balanced chemical reaction presented above, every mole of magnesium (Mg) yields one mole of diatomic hydrogen (H2). When converted to masses, every 24.3 grams of magnesium yields 2 grams of hydrogen.

From the given, there are 20 grams of magnesium available for the reaction. With this amount, the expected yield of hydrogen is 1.646 grams. To calculate the percent yield, divide the actual yield to the hypothetical yield.

*The case is impossible because the actual yield is greater than the theoretical yield.

If we assume that there had been a typographical error and that the actual yield is 0.7 grams instead of 1.7 grams, the percent yield becomes 42.5%. Thus, the answer is letter E.

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3 years ago

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