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scoundrel [369]
3 years ago
7

What is chemistry? I NEED HELP ASAP!

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
3 0

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

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The discovery of a very early form of helium supports the big bang theory because _____.
Amiraneli [1.4K]

Answer:

The discovery of early helium supports the Big Bang Theory because helium is something that would have been a product of a large explosion. Helium is also the most proliferate element in the universe.

Explanation:

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6 0
3 years ago
Read 2 more answers
Calculate the number of grams of solid aluminium chloride that will form when a mixture containing 0.150 g of aluminum powder an
Alinara [238K]

Answer:

the answer is B:) have a good day

5 0
4 years ago
Write the ions present in a solution of na3po4. express your answers as chemical formulas separated by a comma. offset subscript
spin [16.1K]
Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:

(Na)_{3}(PO_{4}) ==> 3 Na^{1+}   +  PO_{4} ^{3-}
6 0
4 years ago
Please help. Is it A. <br> B. <br> C. <br> Or <br> D.?
Serga [27]

Answer:

C

Explanation:

5 0
3 years ago
1.00 mole of oxygen at 60 degrees celcius and 5 bar is flowing through a 20cm diameter pipe (inner diameter). What is the veloci
jeka94

Answer:

u = 0.176 m/x

Explanation:

∴ n O2 = 1 mol

∴ mass O2 = 1 mol * 32 g/mol = 32 g

∴ T = 60°C = 333 K

∴ P = 5 bar

⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)

⇒ V = 5537.124 cm³

∴ d = 20cm

⇒ A = (1/4π)*d² = 314.16 cm²

velocity of the gas (m/x):

  • u = m / ρ*A
  • let time (t) = x sec

∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³

∴ mass flow rate (m) = 32g / x

⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))

⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x

4 0
3 years ago
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