Answer: 2.11cm
Step-by-step explanation:
Given the following :
The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm
The area of trapezoid is calculated using the formula:
1/2(a + b) × h
Where ;
a = Length of side 1
b = length of side 2
h = height
Take a = (2z + 3) and b = (6z – 1), h = z
Therefore ;
1/2 (2z + 3 + 6z - 1) × z
Opening the bracket
(z + 1.5 + 3z - 0.5) × z
(4z + 1 ) × z = 20cm^2
4z^2 + z = 20cm^2
Using Quadratic formula:
4z^2 + z - 20 = 0
a = 4, b = 1, c = - 20
(-b±√b^2 -4ac) / 2a
Z = 2.11 or - 2.364
z cannot be negative, therefore,
Z = 2.11 cm
Step-by-step explanation:
23. area of rect,r = 11 x 3.5 = 38.5cmsq
area of tri, t = 6 x3.5/2 = 10.5 cmsq
area of shaded region, sr = r-t
=> sr = 38.5- 10.5 = 28.5cmsq
24. area of square, s = 10x10 = 100mmsq
area of circle, c = pi x 5^2 = 78.5mmsq
area of shaded region, sr = s - c
=> sr = 100- 78.5 = 22.5mmsq
25. area of circle, c = pi x 6^2 = 113.04insq
area of tri, t = 6x12/2 = 36insq
area of shaded region, sr = c - t
=> sr = 113.04 - 36 = 77.04insq
<span>12 and 4/5
hope that helped =D
</span>
Note that there are 5 exams altogether: 4 hour exams and 1 final exam. Let the grade on the final be x.
The arith. mean of these 5 grades would be
<span>70+ 86+ 81 + 83 + x
</span> course grade = arith. mean = -------------------------------------
5
Answer:
F>110
Step-by-step explanation:
