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oee [108]
3 years ago
12

Question 12(Multiple Choice Worth 5 points) (02.05 MC) Triangle ABC is transformed to obtain triangle A′B′C′: A coordinate grid

is labeled from negative 12 to 0 to 12 on both x- and y-axes at increments of 1. Triangle ABC has A at ordered pair 2, 2, B at 2, 10, C at 8, 12. Triangle A prime B prime C prime has A prime at ordered pair negative 1, negative 1,B prime at negative 1, negative 5, C prime at negative 4, negative 6. Which statement is correct for Triangle ABC. and Triangle A prime B prime C prime.? Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 6. and then rotating it about the origin by 90 degrees Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 2. and then rotating it about the origin by 180 degrees Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 3. and then rotating it about the origin by 180 degrees Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 3. and then rotating it about the origin by 90 degrees
Mathematics
2 answers:
Kobotan [32]3 years ago
8 0

Answer:

 Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 2. and then rotating it about the origin by 180 degrees

hope it helps!

Step-by-step explanation:

shelbyBBB
2 years ago
im running out of time buddy there is no 1/2
shelbyBBB
2 years ago
Triangle ABC is transformed to obtain triangle A′B′C′: A coordinate grid is labeled from negative 12 to 0 to 12 on both x and y axes at increments of 1. Triangle ABC has A at ordered pair negative 12, 12, B at negative 9, 6, C at negative 3, 12. Triangle A prime B prime C prime has A prime at ordered pair 4, negative 4, B prime at 3, negative 2, C prime at 1, negative 4. Which statement is correct for Triangle ABC. and Triangle A prime B prime C prime.? Triangle ABC is similar to triangle A prime B prime C prime. because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 3. and then rotating it about the origin by 180 degrees Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 4. and then rotating it about the origin by 90 degrees Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 4. and then rotating it about the origin by 180 degrees Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 6. and then rotating it about the origin by 90 degrees
NikAS [45]3 years ago
3 0

Answer:

What the other guy said

Step-by-step explanation:

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A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio
Klio2033 [76]

Answer:

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Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

  P(t)=P_0\cdot e^{kt}

We know from the given points that we can write the equation as ...

  P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t

Comparing this to the desired form, we see that ...

  P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693

So, the approximate equation for P is ...

  P(t)=131.836\cdote^{0.032t}

And the parameters of interest are ...

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