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Ahat [919]
2 years ago
13

Simplify and factor if necessary​

Mathematics
1 answer:
Dima020 [189]2 years ago
4 0

Answer:

\frac{1}{x}

Step-by-step explanation:

\frac{3x - 12}{3x^{2}  - 12x}

\frac{3x - 12}{x(3x-12)}          Factor out x.

\frac{1}{x}                    Simplify.

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Help me plz thanks......................
katovenus [111]
The answer is a linear function. For y=8/11x+22

8 0
3 years ago
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4√(-81)+6√(-36)<br> (simplify your answer))
Lapatulllka [165]
When looking at expressions like this,, you need to remember that the square root of a negative number does not exist in the set of Real Numbers. This means that there is no way to simplify this expression,, making the correct answer to your question Undefined.
Let me know if you have any further questions.
:)
3 0
3 years ago
Plz I need help on this
e-lub [12.9K]
Y-intercept = -5
slope = 5/2

Answer:
G
3 0
3 years ago
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Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
Anyone Know This Answer ?
OverLord2011 [107]
I hope this helps you



M^2+R^2=W^2



M^2+16=25



M^2=9
7 0
3 years ago
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