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Andre45 [30]
3 years ago
6

Which is the equation of OB?

Mathematics
1 answer:
GrogVix [38]3 years ago
6 0
The answer is b I hope this helps
You might be interested in
Write the equation of the circle with center (3, 2) and (−6, −4) a point on the circle.
yulyashka [42]
The equation for a circle is as followed:

(x-h)^2+(y-k)^2=r^2

where the center of the circle is at (h,k) and the radius of the circle is r.

We are given (h,k) and need to find the radius. To do so, we can use the distance formula to find the distance from the  center to the point on the circle:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Plug in the two points:

d= \sqrt{(3-(-6))^2+(2-(-4))^2}

d= \sqrt{(9)^2+(6)^2}

d= \sqrt{117}

If the distance from the center to the edge of the circle is the square root of 117, then r^2 = 117.

The answer is:

(x-3)^2+(y-2)^2=117
6 0
3 years ago
Let e be the line through A (-4,5) and B (3. t) that is perpendicular to the line through
grigory [225]

Answer:

Step-by-step explanation:

product of slopes of perpendicular lines=-1

(t-5)/(3+4)×(2-3)/(-4-1)=-1

(t-5)/7×(-1/-5)=-1

(t-5)/35=-1

t-5=-1×35=-35

t=-35+5

t=-30

2.

slopes of parallel lines are equal.

(-2+3)/(t-4)=(-1-4)/(4+2)

1/(t-4)=-5/6

t-4=-6/5

t=4-6/5=(20-6)/5=14/5

3.

x>0,y<0

so P lies in4th quadrant.

except cos and sec all are negative.

so only cos and sec are positive.

8 0
3 years ago
I need help solving this!
blagie [28]

Answer:

miles hybrid car went = 9.80 gal × 54.1 miles/gal

= 530.18 miles

132km × 0.621 = 81.972 miles

530.18 miles = 9.80 gal

1 mile = 9.80/530.18

= 0.018 gal

81.972 miles = 0.018 × 81.972

= 1.515 gal

1.515 gal × 3.785 = 5.734 litres

3 0
4 years ago
The function h (d) = 2d + 4.3 relates the height (h) of the water in a fountain in feet to the diameter (d) of the pipe carrying
mezya [45]

Answer:

h(1.5) = 7.3 ft

h(10.3) = 24.9 ft

Step-by-step explanation:

Given the function h(d) = 2d + 4.3,

where:

h = height of the water in a fountain (in feet)

d = diameter of the pipe carrying the water (in inches)

<h3>h(1.5)</h3>

Substitute the input value of d = 1.5, into the function:

h(1.5) = 2(1.5) + 4.3

h(1.5) = 3 + 4.3

h(1.5) = 7 feet

The height of the water in a fountain is 7 feet when the diameter of the pipe is 1.5 inches.

<h3>h(10.3)</h3>

Substitute the input value of d = 10.3, into the function:

h(10.3) = 2(10.3) + 4.3

h(10.3) = 20.6 + 4.3

h(10.3) = 24.9 feet

The height of the water in a fountain is 24.9 feet when the diameter of the pipe is 10.3 inches.

<h3>Context of the solutions to h(1.5) and h(10.3):</h3>

The solutions to both functions show the relationship between the diameter of the pipe to the height of the water in a fountain.  The height of the water in fountain increases relative to the diameter of the pipe.  In other words, as the diameter or the size of the pipe increases or widens, the height of the water in a fountain also increases.  

3 0
2 years ago
What is the approximate solution to the equation 2^t =38
timurjin [86]

2^t =38

take the log of each side

log ( 2^t) = log (38)

the exponent gets multiplies

t log (2) = log (38)

divide by log 2

t = log(38)/log (2)

t≈5.2479


3 0
3 years ago
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