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2 years ago

If a shape is dilated, do the angles remain the same?

Mathematics

2 answers:

Karo-lina-s [1.5K]2 years ago

6 0

Answer:

yes

Step-by-step explanation:

dilated only makes the shape bigger or smaller

juin [17]2 years ago

3 0

Yes, the angles are the same as the shape is smaller, but it will be a different size

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Bond [772]

Energy transfer is your answer

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3 years ago

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Can you graph a line if its slope is undefined? Explain.

JulijaS [17]

You can but it would be going straight up and down

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3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

Find the area of the figure ABC

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

Find the area of the semicircle

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago

What is the volume of a cone with a diameter of 30 feet and a height of 60 feet? Use 3.14 for π.

AysviL [449]

Answer:

14130 ft^3

Step-by-step explanation:

The formula for the volume of a cone of radius r and height h is

V = (1/3)*pi*r^2*h.

Here, V = (1/3)(3.14)(15 ft)^2*(60 ft) = 20*3.14*225 ft^3 = 14130 ft^3

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2 years ago

Find the Area of RQP

zhannawk [14.2K]

Answer: 25 units squared

Step-by-step explanation:

Draw a line down from p and go right connecting to r. The units there are equal to the ones on the triangle you were given. 5 horizontally and 10 vertically. 5 times 10 is 50 divided by 2

3 0

2 years ago