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Radda [10]
2 years ago
14

Solve the inequality 3(x - 7) + 2(4x + 9) > 0.

Mathematics
2 answers:
Alexandra [31]2 years ago
8 0

Answer:

Step-by-step explanation:

3(x - 7) + 2(4x + 9) > 0

3x-21+8x+18>0

11x-3>0

11x>3

x>3/11

PSYCHO15rus [73]2 years ago
5 0

Answer:

x>3/11

3x - 21 + 8x + 18 >0

11x - 3 >0

11x >3

x>3/11

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You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
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Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

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\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

8 0
3 years ago
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