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3 years ago

Multiply by 4, then divide by 2 First term: 60

Mathematics

1 answer:

natali 33 [55]3 years ago

4 0

120 is what the total would be if you multiplied 60 by 4 and then divided by 2

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2. Koil and Karry want to order the figures from greatest to least

Tom [10]

Given:

Figures A, B and C.

To find:

The order of the figures and volume of each figure.

Solution:

Figure A:

Length = 10, Width = 2 and Height = 2

Volume of A = length × width × height

= 10 × 2 × 2

Volume of A = 40 cubic units

Figure B:

Length = 3, Width = 3 and Height = 1

Volume of B = length × width × height

= 3 × 3 × 1

Volume of B = 9 cubic units

Figure C:

Length = 6, Width = 3 and Height = 3

Volume of C = length × width × height

= 6 × 3 × 3

Volume of C = 54 cubic units

Order from greatest to least:

54 < 40 < 9

C < A < B

Hence Kurry said the correct answer.

7 0

3 years ago

The length of the hypotenuse of a right triangle is 157 units. The length of one leg of the triangle is 132. Lara wrote the foll

ASHA 777 [7]

the correct answer for this is the last choice:

It is incorrect because the length of the unknown side is the square root of 7,225.

4 0

4 years ago

Read 2 more answers

How do you find the value of x for this figure?

Studentka2010 [4]

The 2 lines intersect, and by definition it will create equal opposite angles. Since we know that the angle created is 125 degrees, then the angle on the opposite side also must equal 125 degrees. But wait, they broke up the angle into 2 angles made up of a 64 degree angle and an X degree angle. These 2 angles must add up to 125 degrees.

x + 64 = 125
x = 125 - 64
x = 61 degrees

6 0

3 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$