<span>The first one is false, but the other two are true.
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Answer:
gonna solve fore perimeter and area
P = 12 + 3 + 3 + 9 + 9 + 4 + 4 + 4 = 48cm
P = 48 cm
For area or A it is
A = (12*3) + (4*9) = 72 cm^2
Step-by-step explanation:
use deductive reasoning to determine the missing side lengths, and then solve by splitting the figuring into multiple rectangles
Step-by-step explanation:
Find w
V = lwh
V ÷ lh = w
V/lh = w
w = V/lh
Option → C
So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.
OK, a triangle first of all needs to have a certain condition satisfied. The length of one side of a triangle can not equal the length of 2 sides combined. So in a triangle a + b = c, a + b can not be less than c (a + b <span>≮ c</span>). Therefore, there are only a few possibilities that will work here. Let's find them:
16, 19, 43; no
16, 19, 50; no
16, 43, 50; yes
19, 43, 50; yes
Since only 2 out of 4 form triangles, there is a 50% chance you'll pick the right segments to form a triangle.
