5/8 paper chains used more than 2 containers but less than 2 3/4 containers of glitter.
<h3>
Answer: x-4</h3>
We simply drop the absolute value signs and write whatever is inside
This is because |x-4| is really composed of two equations and it depends on what x is
If x < 4, then we use -(x-4) or -x+4
If x >= 4, then we use x-4
This is from the idea that |x| breaks down into this piecewise function
Replace every x with x-4
Then for each inequality, you would solve for x to get the following
which is the same as
Answer:
mEFD= 90°
mEHF=130°
mHFG=55°
mG=75°
mE=15°
Step-by-step explanation:
mEFD: as you see on the other side of that mEFD there is a right angle. A right angle is =to 90°. An angle on the other side of it has to add up to the 90° angle to equal 180°. Therefore, it equals 90° because 180-90=90
mEHF: so mEHF (or c°) has an angle of 50° on the other side of it. angle c° plus 50° has to equal 180°. Therefore, c°=130 because 180-50=130
mHFG: This one is fairly simple. Since there is already a right angle (90°) when 35°is added to b°, you can figure this out by simple algebra. 90-35=55. The answer to mHFG (b°)= 55°
mG: Now that we know that b°=55° and we have the other angle of the triangle at 50, we just need to add all the angles to equal 180°. so we get 55+50+a°=180. This brings us to a°=180-105. So a°=75°.
mE: since we now know what °c equals (130°) we can solve the answer by equating 130+35+d°=180. we can move 165 on the other side to get d°=180-165. Therefore, d°=15°
In this question , it is given that
your pace on a treadmill is 40.0 meters per minute.
In means 40 meters are travelled in one minute .
And 1 meter equals to 3.28 feet .
So 3.28*40 feet are travelled in one minute, that is
131.2 feets are travelled in 1 minute.
Therefore, 7220 feet are travelled in
Answer:
You can find the answer by using the formula x=-b/2a
Step-by-step explanation:
Remember the maximum height will be at the vertex. The x value of the vertex is your time, so use x=-b/2a. Then if it had also asked what the height was, you would plug that answer into your equation to find the y value of the vertex. Pretty sure your teacher is just asking you to find the x though:)
