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AlekseyPX
3 years ago
14

What is the inverse function of f(x)=6(x-12)^2

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0

y=\sqrt{\frac{x}{6}}+12

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N a​ triangle, the measure of the first angle is twicetwice the measure of the second angle. the measure of the third angle is 6
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2x+x+x+68=180                          
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Angle 1: 56 degrees
Angle 2: 28 degrees
Angle 3: 96 degrees 

I hope that helps.

6 0
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30

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3 years ago
Which of the following is the solution to the equation 3/4 y = 24?
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y = 24 x 4/3
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3 years ago
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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

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3 years ago
Hello pls help besties (o˘◡˘o)
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Hello bestie I cannot help you
8 0
3 years ago
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