One is Iraq! :) (Hope this helps!)
Answer:
The snail will travel 11.75 ft in 5 minutes.
Rule= S(t) = 2.35 t
Explanation:
Since the snail is moving at 2.35 ft per minute, all you have to do is multiply 2.35 by 5 and that's how you get 11.75.
The Rule is the equation that could be used to solve the problem. S represents the snail, and t is how much time the snail travels. To solve from the rule, all you have to do is replace the t in the parenthesis and at the end with a 5 to represent the 5 minutes the snail travels.
Hope this makes sense to you.
F(x) = 2/3x + 1
This is in the slope-intercept form of an equation for a line.
Which is written as this: (Note f(x)= is the same as saying y= in this case)
y = mx + b
M is our slope. Slope is the RISE over the RUN
In other words it is y/x
For this graph y represents distance, and x represents time. (Life Tip: TIME is almost ALWAYS the X value)
In this case M = 2/3
So her speed is:
2 units/3 units
B is the y-intercept. The y-intercept is where the X-value equals 0. So, (0,y). Because the y-intercept is distance she should have a y-intercept of 0. (The origin) because that would mean at the start of the race she had no distance (aka she was at the starting line).
Because her y-intercept (b) = 1 she did have a head start.
Here are both the answers at once to make it easier for you:
Speed (Replace Units with whatever units you were given. Distance Units go on top. Time units on bottom. Example: Meters/Second))
2 units/3 units
Did she have a head start? (Unit being whatever distance unit you were given)
Yes, 1 unit.
<h3><u>MEAN</u></h3>
Mean is the average. To find the mean of a data set, you have to add all the numbers and divide the sum by the amount of numbers you added.
<em>In this equation, you have 8 numbers. That means you will be dividing by 8. </em>
The first thing you need to do is add all the numbers. Add:

Now that you have added all the numbers and got the sum, divide by 8. Remember that you will be dividing by 8 since you added 8 numbers.
Divide:

The mean is 66
<em>If you have any questions, feel free to ask in the comments! :)</em>