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BartSMP [9]
3 years ago
7

What is the mean of 72,73,86,59,75,58,50,55

Mathematics
2 answers:
Rashid [163]3 years ago
7 0
<h3><u>MEAN</u></h3>

Mean is the average. To find the mean of a data set, you have to add all the numbers and divide the sum by the amount of numbers you added.

<em>In this equation, you have 8 numbers. That means you will be dividing by 8. </em>

The first thing you need to do is add all the numbers. Add:

72+73+86+59+75+58+50+55 = \bf 528

Now that you have added all the numbers and got the sum, divide by 8. Remember that you will be dividing by 8 since you added 8 numbers.

Divide:

528 \div 8 = \bf 66

The mean is 66

<em>If you have any questions, feel free to ask in the comments! :)</em>

alexdok [17]3 years ago
7 0
The answer is 66.

Step by step explanation:
First, add all of the numbers together.
Then, divide the sum of the numbers by the number of entries you see.

Since there’s 8 numbers, you divide it by 8.
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A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

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Answer:

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