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Alina [70]
2 years ago
7

The radius of a basketball is approximately 12. Icm. What is the volume of the basketball?​

Mathematics
2 answers:
jeka57 [31]2 years ago
5 0

Answer:

7238

Step-by-step explanation:

That's the answer....

just olya [345]2 years ago
4 0

Answer:

A = 4πr2                            

do you understand this?

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!!!!!!!please help!!!!!!!!
GuDViN [60]

Answer:

The first one is No. The second one I do not know unfortunately.

Step-by-step explanation:

I am in the middle of this lesson in my math class as well and I know that in order to make a triangle, you need the two smaller sides to add up to become larger than the biggest side. In the case of the first question, the two smaller sides, 6 and 3 equal 9, which is not bigger than the biggest side which is 10. I hope you can find the answer to the second one, but for now, the first one is No.

4 0
2 years ago
Please help me out I need it done ASAP
irinina [24]
Your answer will be letter c
7 0
3 years ago
in a circle a 60 sector has an area of 25 pi square feet. what is the circumference? leave your answer in terms of pi and in sim
belka [17]
The area of the sector is given by the equation,
                           A = πr²(x / 360°)
where x is the number of degrees in the figure. 
                           25π ft² = (πr²)(60/360)
The value of  r is 12.25 ft. Then, we use this value to calculate for the circumference of the sector. 
                           C = 2πr(x/360)
Substituting,
                              C = 2π(12.45)(60/360)
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7 0
3 years ago
Natalie has 48 tiles write a factor pair for the number 48
grandymaker [24]
A factor is a number multiplied by another factor to get a product:
a x b = c
a and b are factors and c is product.
So, for 48, factor pairs are:

1 x 48
2 x 24
3 x 16
4 x 12
6 x 8
8 x 6
12 x 4
16 x 3
24 x 2
48 x 1 
8 0
3 years ago
If alpha beta are the roots of the equation
Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }

Thank you

8 0
2 years ago
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