Is Y = 2’x -5 a linear or nonlenear
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Well, the area of a trapezoid is A = (
+ 
) * h * 1/2 so you can use the area of a parallelogram, which is A = l * w, by splitting the trapezoid into 2 triangles and one rectangle. So you'd use A = l * w for the rectangle and A = 1/2bh for the triangles. You'd get the same answer!
