Given:
There are given the edge of the cube-shaped aquarium has 3 feet.
Explanation:
To find the value, we need to use the volume of the cube formula:
So,
From the formula of volume:
Where
a represents the value of edge.
So,
Put the value of edge into the above formula:
Then,
Now,
The water has a density of 62 pounds per cube foot.
According to the question:
If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:
Final answer:
Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.
And,
No, the density of water would not change.
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Answer: I got 32
Step-by-step explanation:
I got 32
Step-by-step explanation:
-2x+3=x+12
combin like terms
-2x-x=12-3
-3x=9
x=9/-3
x=-3
