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2 years ago

Solve

Mathematics

1 answer:

victus00 [196]2 years ago

3 0

Answer:

x=14 , y = 21

Step-by-step explanation:

y=x-7...............1

5x+2y=7......2

reset eqn .....2

2y=-5x+7

so; y=-x-7 ×5

2y=-5x+7 ×1

5y = -5x -35

2y = -5x +7

5y-2y = -5 + 5 -35-7

3y = - 42

3 3

y = 14

sub y=14 into eqn ...........1

y = -x -7

14 = - x -7

14 +7 = - x

-21 = x

x = 14 , y =-21

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Part A

The height to which the projectile reaches is given by the following formula;

$\Delta y = y-y_0 = v_{0y} \times t-\dfrac{1}{2} \times g \times t^2$

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Part B

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y = Δy + y₀

The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, $y_i$

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Step-by-step explanation:

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Answer:

$\large{\boxed{\sf 2y^2\sqrt{2y}}}$