Answer:
There needs to be an odd number of 1 bits
Explanation:
In memory, parity checking method is used to test the memory. There are two parity conditions. Either the parity is even or the parity is odd.
Odd parity means, number of 1's in eight bits of data. If the number 1's are odd it means parity is odd. In case of the memory testing result the parity should be odd.
So, In case of Parity of RAM, the parity should be odd, if the data is stored in the RAM.
It can be noisy and distracting to students to listen to audio speakers when there are multiple computers in the classroom. Headphones help the students
Answer:
People prefer composite faces.
Explanation:
If we take some face's picture, and we make it digital, we could make a composite or averaged face, and when we compare composite faces with originals pictures, people prefer the composite faces because there was symmetry in those faces.
For example:
There was a research where a digitalized student faces men and women, researchers make a composite face for every original, people prefer composite face against the original face.
Answer:
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i = 0;
int matchValue = 0;
int numMatches = -99; // Assign numMatches with 0 before your for loop
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
numMatches=0;
for(i=0;i<NUM_VALS;i++)
{
if(userValues[i]==matchValue)//cheking if the array element is equal to match value.
{
numMatches++;
}
}
System.out.println(numMatches);//printing the matchvalue.
}
}
Output:-
3
Explanation:
First I have set the value numMatches to 0 before the loop.Then I have user the for loop to iterate over the array.In the for loop I am checking that the array element is equal to the matchValue or not if it is equal then increasing the numMatches by 1.Then at last print the value of numMatches.
