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svp [43]
3 years ago
8

Which of these galaxies can be shaped as a single spiral arm?

Advanced Placement (AP)
2 answers:
nlexa [21]3 years ago
6 0

The most common type of galaxy found throughout the universe is the spiral galaxy. Around 77% of the galaxies observed by man are spiral galaxies. A good example of this type is the Andromeda galaxy. Around two-thirds of all spiral galaxies have a bar-like structure – thus they are classified as barred spiral galaxies. The file attached shows how to figure out weather its a spiral galaxy or not.

Keith_Richards [23]3 years ago
6 0

Answer: C. Magellanic spiral galaxies

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Help!! Need help with these questions ITS AP MICRO
adelina 88 [10]

Answer:

a's answer is India

Explanation:

india has 10 millions pounds of peanuts but the US has only 1 million pounds of peanut

8 0
2 years ago
True or false: A speaker should aim to be simple, rather than complex.
Lorico [155]
I believe it is true because if speaker is too complex he/she would tend to lose the audience. Hope this is correct :)
8 0
3 years ago
Read 2 more answers
Among the social institutions that promote nationalism, the three most important are:
Marina CMI [18]
The family is not very strong at promoting nationalism: for once, there can be family members of other nationalities, which would promote multinationalism! so we can reject a) and c)

now, military and state religion are both found in the other options and we have to choose between school and athletics - and school is more effective! so the correct answer is D.
8 0
3 years ago
Which of the following is the same as (V3+V2)2 ?
Drupady [299]
Solution. To check whether the vectors are linearly independent, we must answer the following question: if a linear combination of the vectors is the zero vector, is it necessarily true that all the coefficients are zeros?
Suppose that
x 1 ⃗v 1 + x 2 ⃗v 2 + x 3 ( ⃗v 1 + ⃗v 2 + ⃗v 3 ) = ⃗0
(a linear combination of the vectors is the zero vector). Is it necessarily true that x1 =x2 =x3 =0?
We have
x1⃗v1 + x2⃗v2 + x3(⃗v1 + ⃗v2 + ⃗v3) = x1⃗v1 + x2⃗v2 + x3⃗v1 + x3⃗v2 + x3⃗v3
=(x1 + x3)⃗v1 + (x2 + x3)⃗v2 + x3⃗v3 = ⃗0.
Since ⃗v1, ⃗v2, and ⃗v3 are linearly independent, we must have the coeffi-
cients of the linear combination equal to 0, that is, we must have
x1 + x3 = 0 x2 + x3 = 0 ,
x3 = 0
from which it follows that we must have x1 = x2 = x3 = 0. Hence the
vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer. The vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
4 0
3 years ago
C. (C+ 12d=-100<br> -4c73d=-42
rosijanka [135]

Answer:

C

Explanation:

Positive charge

6 0
3 years ago
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