Answer:
B)
Step-by-step explanation:
(2x^3+x^2-4x)-(9x^3-3x^2)
2x^3-9x^3+x^2-(-3x^2)-4x
-7x^3+x^2+3x^2-4x
-7x^3+4x^2-4x
Velocity is given as 80 feet per second, so replace V with 80.
The rocket is launched from the ground so the initial height is 0, so replace h with 0
The formula now becomes" h(t) = -16t^2 + 80t +0
To find the maximum we need to find the coordinates of the vertex by finding the axis of symmetry:
-b/2a = -80/(2*-16) = -80/-32 = 2.5
This represents the amount of time for the rocket to reach maximum height.
So we now replace t in the equation with 2.5 and solve for the height:
h(2.5) = -16(2.5)^2 + 80(2.5)
h(2.5) = 100
The maximum height is 100 feet
Answer:
Step-by-step explanation:
Since the outdoor ice skating arena is in the shape of a circle, we would determine its area by applying the formula for determining the area of a circle which is expressed as
Area = πr²
Where
π is a constant whose value is 3.14
r represents the radius of the circle
From the information given,
Diameter = 42 feet
Radius = diameter/2 = 42/2 = 21 feet
Therefore,
Area = 3.14 × 21² = 1384.74 square feet
Rounding up to the nearest whole number, area of the outdoor ice skating arena would be 1385 square feet
A = 1/4 = 0.25 = 25%
b = 1/16 = 0.0625 = 6.25%
c = 1/8 = 0.125 = 12.5%
d = 1/4 = 0.25 = 25%
Answer:
6,400
Step-by-step explanation:
d=16t^2
t=20
Replace t with 20 because 20 = second
d=16(20)^2
d=16(400)
d=6,400
