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3 years ago

Can anyone help? If arcLM = 8x-56 and arcNP = 5x+22, find arcLP.

Mathematics

1 answer:

Mashcka [7]3 years ago

4 0

Answer:

arcLP = 19

Step-by-step explanation:

Given the following

arcLM = 8x-56

arcNP = 5x+22

Required

arcLP

Given that arcLM = arcNP

8x-56 = 5x+22

8x - 5x = 22 + 56

3x = 78

x = 78/3

x = 26

Let assume arcLP = x - 7

arcLP = 26 -7

arcLP = 19

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$\dfrac{dP(t)}{P(t)} =k dt\\$Take the integral of both sides\\\int \dfrac{dP(t)}{P(t)} =\int k dt\\\ln P(t)=kt+C, $C a constant of integration\\Take the exponential of both sides\\e^{\ln P(t)}=e^{kt+C}\\P(t)=e^{kt}\cdot e^C $, (Since e^C$ is a constant, we then have:)\\P(t)=Ce^{kt}$