$C(0,3) \\
x_1=0 \\
y_1=3 \\ \\
D(4,7) \\
x_2=4 \\
y_2=7 \\ \\
\overset{\underline{\ \ \ \ }}{CD} =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(4-0)^2+(7-3)^2}= \\
=\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{16 \times 2}=4\sqrt{2} \\ \\
\boxed{\overset{\underline{\ \ \ \ }}{CD} = 4\sqrt{2}}$

7 0

3 years ago

Help please image is uploaded view please.

harina [27]

Answer:

Step-by-step explanation:

we are given that angle NRQ is 78 degrees

we can see from the figure that the sum of the given angles is angle NRQ

(8x + 7) + (4x - 1) = 78

12x + 6 = 78

12x = 72

x = 6

Now, we have to find angle PRQ

replacing x with 6 in the equation of angle PRQ

PRQ = 4(6) - 1

PRQ = 23

6 0

3 years ago

The mark obtained by Belij in an exam is 28 out of 40, express his obtained marks in percentage

Brut [27]

Marks

= 28/40

= 28/40 × 2.5/2.5

= 70/100

= 70%

5 0

3 years ago

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