V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
The anwser is one and two tenths
We saw under Functional Notation that y = 3x + 2 and f (x) = 3x + 2 can be interpreted as equivalent notations, where y has been replaced by f (x), or y = f (x). In y = 3x + 2, we see “y as a function of x”
Answer is 7.
55+5X=90
5X=90-55
5X=35
X=35/5
X=7
Answer:
y=3x-2
Step-by-step explanation: