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ratelena [41]
3 years ago
10

On the grid, draw graphs of y=x+2 and x+y=3

Mathematics
2 answers:
ANTONII [103]3 years ago
6 0

Answer:

The image shows the answer and below I will explain more about it.

Step-by-step explanation:

To draw a line all you need is two points on the graph, and people mainly use the coordinates of the y and x intercepts to draw it (when x=0 and when y=0)

so for these questions all we do is:

y=0+2 (we are putting x=0 into the equation)

y=2, x=0 so this is the first of our set of coords:

0=x+2

x=-2 y=0 (we are putting y=0 into the equation)

so all you do is plot these in and draw a line which passes between both,

now just repeat for the other one :)

masya89 [10]3 years ago
4 0
Try getting a graphing calculator they help a lot

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A total of 559 tickets were sold for the school play. They were either adult tickets or student tickets. There were 59 more stud
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Answer: The answer is 500 hope this helps!

Step-by-step explanation:

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How many variables are displayed in a scatterplot?
vampirchik [111]
One along the X-axis and one along the y- axis
5 0
3 years ago
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

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3 years ago
The sum of 15 and the product of 5 and v
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By using the table in the handbook, the present value of $12,000 for six years compounded at 6 percent semiannually is
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Take a look at the attachment to see the solution.
A = future value
P = principal (P = 12,000)
r = interest rate (r=6)
n = time periods (n=12)

6 0
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