How to Draw Parallel Lines:
1. Draw a straight line any length

2. Draw another straight line any length

(note : ensure the lines will never intersect)

They shall never horizontally or vertically.

How to Draw Perpendicular Lines:
1. Draw a straight line vertically

2. Draw a straight line horizontally

(note : length does not necessarily matter)

The two lines must cross at right angles to each other!!

With the parallel line instructions, simply just draw lines but, when given the slopes of two lines, you must get graphing paper or make your own, and graph it by plotting points and then getting a ruler and tracing it.

With the perpendicular lines it helps with showing a relation between situations along with given slopes. They shall intersect always and meet at a 90° angle. Use the equations and plot them then take a ruler and trace them and notice the intersection. Solve it yourself and see that the intersection and the answers you got are the same.

5 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Ierofanga [76]

The area of the triangle is $2\sqrt{3}$ = 3.4641 square feet.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.

In the given triangle, the hypotenuse is the side that is represented by c. The other sides on the triangle are represented by the values a and b.

Step 2:

Assume the other side of the triangle measures x units.

So according to the Pythagorean theorem,

$4^{2} = (2\sqrt{3} )^{2} + x^{2} , x^{2} = 4^{2} - (2\sqrt{3} )^{2} .$

$x^{2} = 16 - 12 =4, x =2.$

So the other side of the triangle, b measures 2 feet.

Step 3:

The area of a triangle is half the product of its base length and height.

The base length of this triangle is $2\sqrt{3}$ feet and the height is 2 feet.

The area of the triangle $= \frac{1}{2} (2\sqrt{3} )(2) = 2\sqrt{3} = 3.4641.$

The area of the triangle is $2\sqrt{3}$ = 3.4641 square feet.

3 0

3 years ago

How do you find the radius of a Tetrahedron?

BigorU [14]

Answer:

The center of the tetrahedron divides each of the four heights (or medians) in the ratio 1:3 (in an equilateral triangle the corresponding ratio is 1:2). The smaller part is also the radius of the inscribed sphere. Therefore the radius of this sphere is one quarter of the height or 9 in your case.

6 0

2 years ago