Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
we know there are 5280 feet in 1 mile, and there are 3600 seconds in 1 hour.
The answer to (3x-1)2=5 is x= 7/6
Answer:
The answer is V = π r 2h
Trust me i just got this question and that was the answer.
Step-by-step explanation:
The general and correct rule in order of operations is PEMDAS which is parentheses, exponents, multiplication, division, addition then subtraction.
Given the expression <span>2 + (3 + 5)2 ÷ 4 ⋅(1/2)^4
P : </span><span>2 + (8)2 ÷ 4 ⋅(1/2)^4
E : </span><span>2 + (8)2 ÷ 4 ⋅ 0.0625
M: </span><span>2 + 16 ÷ 0.25
D: 2 + 64
A: 66
S: -
The final answer is then 66.</span>
