Answer:
the answer for the question is 10+x
y-3
Given:
Line A: 2x + 2y = 8
Line B: x + y = 4
x = 4 - y
2(4-y) + 2y = 8
8 - 2y + 2y = 0
0 = -8
y = 4 - x
2x + 2(4-x) = 8
2x + 8 - 2x = 8
0 = 0
There is no solution.
Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.
The relation 2+4+6+...+2n = n^2+n has to be proved.
If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2
Assume that the relation holds for any value of n.
2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)
= n^2 + n + 2n + 2
= n^2 + 2n + 1 + n + 1
= (n + 1)^2 + (n + 1)
This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.
<span>By mathematical induction the relation is true for any value of n.</span>
Answer: 210
Step-by-step explanation:
We know that the number of combinations of n things taken r at a time is given by :-
So, number of ways to select 3 plants out of 7 = 
Also number of ways to arrange them in 3 positions = 3! = 6
Now , total number of arrangements with 1 plant in each spot = (number of ways to select 3 plants out of 7) x (number of ways to arrange them in 3 positions)
= 35 x 6
=210
Hence, required number of ways = 210
