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3 years ago

Thank you I will give you the brain thing and extra points. (image below) 5/13

Mathematics

2 answers:

asambeis [7]3 years ago

8 0

Answer:

Hi how are you doing today

NikAS [45]3 years ago

7 0

Answer:

I'm pretty sure it's C

Step-by-step explanation:

To be a function no two inputs can have the same output. An input can have two different outputs. So it would again be C

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Lauren coordinates a construction projects for a cement company. A government project requires constructing two rectangular conc

I am Lyosha [343]

Answer:

Step-by-step explanation:

Total concrete for slabs

24 * 24 * 1 = 576 ft³

Additional 20 %

By rule of three

if 576 ⇒ 100

x?? ⇒ 20 x = 115,2

And there are 2 slabs, the total volume of concrete is:

Q(t) = 2* (576 + 115,2 ) Q(t) = 1382,4 ft³ (1)

If the truck can carry a maximum of 8 yd³, as 1 ft³ = 0,037 yd³

then a truck can carry a maximum of

8/ 0,037 = 216,21 ft³

Now the total quantity is 1382,4

Then

1382,4/216,21 = 6,39

And as nobody can send a fraction of a truck , the fewest number of truck is 7

5 0

3 years ago

Susan bought 12 ounces of candy. How many pounds did she buy?<br> Show the proportions needed

DedPeter [7]

Answer:

If Susan bought 12 ounces that would equal to .75 pounds

Step-by-step explanation:

4 0

2 years ago

A bag contains 10 red marbles, 15 yellow marbles and 5 green marbles. What is the probability of drawing a red or green marble f

Volgvan

Probability =

(number of ways it can come out the way you want)
divided by
(total number of ways it can come out).

Total number of ways to draw a marble = 30 (marbles in the bag).

Number of ways it can succeed = 15 (number of red or green ones)

Probability = 15/30 = 1/2 = 50% .

8 0

2 years ago

Read 2 more answers

9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9

gladu [14]

Answer: a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

$x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)$

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

$\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976$