Domain and range should be (-&,-&)
There are a total of 8 letters in student, with 6 different letters ( there are 2 s's and 2 t's).
First find the number of arrangements that can be made using 8 letters.
This is 8! which is:
8 x 7 x 6 x 5 x 4 3 x 2 x 1 = 40,320
Now there are 2 s's and 2 t's find the number of arrangements of those:
S = 2! = 2 x 1 = 2
T = 2! = 2 x 1 = 2
Now divide the total combinations by the product of the s and t's:
40,320 / (2*2)
= 40320 / 4
= 10,080
The answer is A. 10,080
Answer:
hello :
note :
the nth term of an arithmetic sequence is :
An =A1+(n-1)d ....a common difference is : d ... A1 : the first term
in this exercice : A1 = - 1 d = (-6) -(- 1) = -5
An = - 1 + (n - 1)(-5)
the expression is : An = - 5n +4
<span>300 + 70 + 6 is the right answer
</span>
Answer:
0.923
Step-by-step explanation:
There are 13 total marbles. (12 Purple Marbles + One Blue Marble)
The total events are 13 and the number of preferred events is 12.
≈ 0.923
So there should be a 0.923 chance that a purple marble is picked.
