Answer:
From top to bottom: 
A, J, E, B, I, C, D, G, F, H
See below for more clarification. 
Step-by-step explanation:
We are given that AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. And we want to prove that ΔAEB ≅ ΔDEC. 
Statements: 
1) XY is perpendicular to AB. 
Definition of perpendicular bisector. 
2) XY ⊥ CD. 
In a plane, if a transveral is perpendicular to one of the two parallel lines, then it is perpendicular to the other. 
3) m∠AXE = 90°, m∠DYE = 90°. 
Definition of perpendicular lines. 
4) ∠AXE ≅ ∠DYE. 
Right angles are congruent. 
5) XE ≅ YE
Definition of a midpoint. 
6) ∠A ≅ ∠D. 
Alternate Interior Angles Theorem
7) ΔAEX ≅ ΔDEY
AAS Triangle Congruence*
(*∠A ≅ ∠D, ∠AXE ≅ ∠DYE, and XE ≅ YE)
8) AE ≅ DE
Corresponding parts of congruent triangles are congruent (CPCTC). 
9) ∠AEB ≅ ∠DEC
Vertical Angles Theorem
10) ΔAEB ≅ ΔDEC
ASA Triangle Congruence**
(**∠A ≅ ∠D, AE ≅ DE, and ∠AEB ≅ ∠DEC)