The price of a Tesla Model X was bought for \$80,000 and has depreciated 10.2% yearly. Find the price of the car 3 years later

I am having trouble<br> 2(10-13x)=-34x+60

morpeh [17]

<span>Simplifying 2(10 + -13x) = -34x + 60
(10 * 2 + -13x * 2) = -34x + 60
(20 + -26x) = -34x + 60
Reorder the terms: 20 + -26x = 60 + -34x
Solving 20 + -26x = 60 + -34x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '34x' to each side of the equation. 20 + -26x + 34x = 60 + -34x + 34x
Combine like terms: -26x + 34x = 8x 20 + 8x = 60 + -34x + 34x
Combine like terms: -34x + 34x = 0 20 + 8x = 60 + 0 20 + 8x = 60
Add '-20' to each side of the equation. 20 + -20 + 8x = 60 + -20
Combine like terms: 20 + -20 = 0 0 + 8x = 60 + -20 8x = 60 + -20
Combine like terms: 60 + -20 = 40 8x = 40
Divide each side by '8'. x = 5
Simplifying x = 5</span>

7 0

3 years ago

What is the radius of the sun?

Harrizon [31]

432,288 miles.
Google something like this lol

5 0

3 years ago

Last year the girl's basketball team had 8 fifth-grade students and 7 sixth-grade students.What was the ratio of sixth-grade stu

Rashid [163]

Answer:

The ratio of sixth-grade students to fifth-grade students on the team was <u>7 : 8</u>.

Step-by-step explanation:

Given:

The girl's basketball team had 8 fifth-grade students and 7 sixth-grade students.

Now, to find the ratio of sixth-grade students to fifth-grade students on the team.

<em>Number of fifth-grade students = 8.</em>

<em>Number of sixth-grade students = 7.</em>

Now, to get the ratio of sixth-grade students to fifth-grade students on the team :

$Number\ of\ sixth-grade\ students:Number\ of\ fifth-grade\ students$

$=7:8.$

Therefore, the ratio of sixth-grade students to fifth-grade students on the team was 7 : 8.

4 0

3 years ago

sidney writes two equations: I = 350n and E = 150n + 1000. The equations relate income I and operating expenses E to number of c

maria [59]

9514 1404 393

Answer:

600, 1400, 3000, and 5000

Step-by-step explanation:

The profit equation can be simplified.

P = 350n -(150n +1000)

P = 200n -1000 . . . . . . . . . collect terms

P = 200(n -5) . . . . . . . . . . . factor out 200

For the given numbers n, we have ...

P = 200({8, 12, 20, 30} -5) = 200{3, 7, 15, 25} = {600, 1400, 3000, 5000}

Profits for 8, 12, 20, and 30 customers are 600, 1400, 3000, and 5000, respectively.

7 0

3 years ago

40 points plz help if u can Which function has no Zeroes? Select all that apply.

Damm [24]

<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

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Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

y = cot(x)
y = sin(x)
y = tan(x)

So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

sec(x) = 1/cos(x)

7 0

3 years ago