<span>So there are 33 boys who tried out for track. And this is 27.5 % of the total boys. And there 15% of the girls who tried out for the track. And in total 22.5 % of the total population tried out for track</span>

5 0

2 years ago

Bill's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 5 adult tickets and 14 st

wariber [46]

Answer: The price of an adult ticket = $6

The price of a student ticket = $12

Step-by-step explanation:

Let the price of an adult ticket be a

Let the price of a student ticket be b.

From the question,

5a + 14b = 198 ...... equation i

10a + 8b = 156....... equation ii

Multiply equation i by 10

Multiply equation ii by 5

50a + 140b = 1980 ...... equation iii

50a + 40b = 780 ....... equation iv

Subtract iv from iii

100b = 1200

b = 1200/100

b = 12

Put the value of b into equation ii

10a + 8b = 156

10a + 8(12) = 156

10a + 96 = 156

10a = 156-96

10a = 60

a = 6

The price of an adult ticket = $6

The price of a student ticket = $12

8 0

2 years ago

Factor completely y^2-xy-56x^2

olga2289 [7]

You can factor this out by thinking of the factors of 56 that have a sum of -1. 7 and 8 are factors of 56 and to get a sum of -1, 8 should be negative. 7 + -8 = -1

So $y^{2} - xy - 56x^{2}$ factored out is (y+7x)(y-8x)

We can check this using FOIL
F = (y)(y) = $y^{2}$
O = (y)(-8x) = -8xy
I = (7x)(y) = 7xy
L = (7x)(-8x) = $-56x^{2}$
$y^{2} - 8xy + 7xy - 56x^{2}$ Combine like terms
$y^{2} - xy - 56x^{2}$

3 0

2 years ago

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