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Anna71 [15]
3 years ago
6

When you see a problem like -17 - (-7) what do you do first

Mathematics
1 answer:
Karolina [17]3 years ago
6 0
You have to add -17+(-7) when you get (-7) you have to add.
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How do I do this? I’m not sure can anyone help?
eduard

value of x= 7√3

Hope it helps you...

8 0
2 years ago
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How to find if a function is positive or negative?
stiks02 [169]
Positive because a function is beetween and past
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3 years ago
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
2 years ago
Simplify. 4 + 3 • (7 – 2) A. 19 B. 35 C. 47 D. 12
makvit [3.9K]
4 + 3 * (7 - 2)
4 + 3 * 5
4 + 15
19 <==
8 0
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14. Which of the following is true about given APQR given in Figure 7.82 to the right? a. p²+q²=² b. q²+r²=p² c. (p+q)²=r² d. p²
Cloud [144]
Answer :
a. p²+q²=r²

According to the Pythagorean theorem :
p²+q²=r² ,because this is a right triangle and r is the length of the hypotenuse.
8 0
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