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3 years ago

When you see a problem like -17 - (-7) what do you do first

Mathematics

1 answer:

Karolina [17]3 years ago

6 0

You have to add -17+(-7) when you get (-7) you have to add.

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As an estimate we are told 5 miles is 8km. Convert 80km to miles

romanna [79]

49.71 miles is the answer

4 0

2 years ago

8) A school community had planned to reduce the number of grade 9 students per class room by constructing additional class rooms

Allisa [31]

Step-by-step explanation:

Let "c" be the original number of classrooms.

The 1200/c was the original number of students per classroom.

----

Equation:

1200/(c-4) = (1200/c)+10

Multiply thru by c(c-4)

---

1200c = 1200(c-4)+10c(c-4)

---

1200c = 1200c-4800 + 10c^2-40c

----

10c^2-40c-4800 = 0

c^2-4c-480 = 0

Factor:

(c-24)(c+20) = 0

---

Positive solution:

c = 24 (# of classrooms originaly planned)

7 0

2 years ago

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Alina [70]

we know that

Area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius

in this problem

$diameter=12\ in \\ radius=diameter/2\\ radius=12/2\\ radius=6\ in$

$A=3.14* 6^{2}$

$A=113.04 in^{2}$

therefore

the answer is the option

d. 113.04 sq. in.

8 0

3 years ago

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QUICK PLEASE HELP. I'm offering 15pt and brainliest answer.

worty [1.4K]

X would be equal to 6

4 0

3 years ago

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. If α and β are the roots of

Lostsunrise [7]

Answer:

$18x^2+85x+18 = 0$

Step-by-step explanation:

Given Equation is

=> $2x^2+7x-9=0$

Comparing it with $ax^2+bx+c = 0$ , we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = $-\frac{b}{a}$

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

Now, Finding the equation whose roots are:

α/β ,β/α

Sum of Roots = $\frac{\alpha }{\beta } + \frac{\beta }{\alpha }$

Sum of Roots = $\frac{\alpha^2+\beta^2 }{\alpha \beta }$

Sum of Roots = $\frac{(\alpha+\beta )^2-2\alpha\beta }{\alpha\beta }$

Sum of roots = $(\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}$

Sum of roots = $\frac{49}{4} + 9 /\frac{-9}{2}$

Sum of Roots = $\frac{49+36}{4} / \frac{-9}{2}$

Sum of roots = $\frac{85}{4} * \frac{2}{-9}$

Sum of roots = S = $-\frac{85}{18}$

Product of Roots = $\frac{\alpha }{\beta } \frac{\beta }{\alpha }$

Product of Roots = P = 1

The Quadratic Equation is:

=> $x^2-Sx+P = 0$

=> $x^2 - (-\frac{85}{18} )x+1 = 0$

=> $x^2 + \frac{85}{18}x + 1 = 0$

=> $18x^2+85x+18 = 0$

This is the required quadratic equation.

5 0

3 years ago

Read 2 more answers