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Maslowich
3 years ago
8

Calculate the curved surface area of a cylindrical container 10cm diameter, length 18cm take the value of pie to 3.14

Mathematics
1 answer:
True [87]3 years ago
6 0

Answer:

56.52 cm^2

Step-by-step explanation:

curved surface area = 2πrh

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

10 / 2 = 5

2 x 3.14 x5 x 18 = 56.52 cm^2

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Can you please help me
Iteru [2.4K]

Answer:

the answer is 320

Step-by-step explanation:

144 divided by 0.45 equals 320

and for checking my answer 320 times 0.45 equals 144

so 320 is your answer i hope this helps

6 0
3 years ago
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How is the distributive property used to expand expressions? provide an example
Pepsi [2]
Yes the distributive property is used to expand expressions, but it is also used to make it simpler.
For an example

3(x+4) + 3(y-8)
This is the same thing as
3x + 12 + 3y -8
8 0
3 years ago
Consider the graph of f(x) = x is shifted up 8 units, what would be the equation of the new graph?
anygoal [31]
F(x) = x + 8

This is because you are simply moving the y-intercept up 8 units.

Please consider marking this answer as Brainliest to help me advance.
5 0
3 years ago
A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
The measures of two angles are 4x° and (2x + 12)°. What must be true if x = 13
tatiyna
Yeas the answer is B
5 0
3 years ago
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