What is the value of x?

Mathematics

2 answers:

Tpy6a [65]2 years ago

6 0

90 I think I really could be wrong and if I am I am super sorry

dlinn [17]2 years ago

3 0

I believe it’s 90. Not sure though.

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Solve for x. 2x+5+6x-1=120

svetlana [45]

Answer:

x=14.5

Step-by-step explanation:

2x+5+6x-1=120

Combine like terms (combine all of the variables and then combine all of the constants)

8x+4=120

subtract 4 on both sides

8x=116

Divide 8

x=14.5

Hope this helps!

8 0

3 years ago

An observer in tower A sees a boat 1538 yd away at an angle of depression of 35°. To the nearest yard, how far is the boat away

Thepotemich [5.8K]

From my own solution, my answer is closest to D. 1951 yd; 27°

The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27°.

Pls. see my attachment.

In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin θ = opposite / hypotenuse

sin 35° = opposite / 1538 yd
sin 35° * 1538 yd = opposite
882.16 yd = opposite

From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.

I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.

Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.

With regards to the angle of depression, I used this formula:

tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14°

8 0

4 years ago

Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have: