There is no figure, i cant help you sorry
The coordinates of point B are (-4 , -2) ⇒ answer H
Step-by-step explanation:
In any circle
- The diameter of the circle passing through its center
- The center of the circle is the mid-point of all diameters
If (x , y) are the coordinates of the mid-point of a line whose end
points are
and
, then
and 
∵ Point C is the center of a circle
∵ AB is the diameter of the circle
∴ C is the mid point of AB
∵ A = (2 , 6) ⇒ 
∵ B = 
∵ C = (-1 , 2) ⇒ (x , y)
- Use the rule of the mid-point above
∵ 
- Multiply both sides by 2
∴ -2 = 2 + 
- Subtract 2 from both sides
∴
= -4
∴ The x-coordinate of point B is -4
∵ 
- Multiply both sides by 2
∴ 4 = 6 + 
- Subtract 6 from both sides
∴
= -2
∴ The y-coordinate of point B is -2
The coordinates of point B are (-4 , -2)
Learn more:
You can learn more about the circle in brainly.com/question/9510228
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Answer:
r = (ab)/(a+b)
Step-by-step explanation:
Consider the attached sketch. The diagram shows base b at the bottom and base a at the top. The height of the trapezoid must be twice the radius. The point where the slant side of the trapezoid is tangent to the inscribed circle divides that slant side into two parts: lengths (a-r) and (b-r). The sum of these lengths is the length of the slant side, which is the hypotenuse of a right triangle with one leg equal to 2r and the other leg equal to (b-a).
Using the Pythagorean theorem, we can write the relation ...
((a-r) +(b-r))^2 = (2r)^2 +(b -a)^2
a^2 +2ab +b^2 -4r(a+b) +4r^2 = 4r^2 +b^2 -2ab +a^2
-4r(a+b) = -4ab . . . . . . . . subtract common terms from both sides, also -2ab
r = ab/(a+b) . . . . . . . . . divide by the coefficient of r
The radius of the inscribed circle in a right trapezoid is r = ab/(a+b).
_____
The graph in the second attachment shows a trapezoid with the radius calculated as above.