Answer:
let seat as x,
and snack as y.
so the linear equation is 20x+5y=400.
You ran 6 miles on the treadmill on Monday.
Using the information from the question, one can construct two equations:
![4 z = x](https://tex.z-dn.net/?f=4%20z%20%3D%20x)
... (1)
![\frac{1}{z} + \frac{1}{x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bz%7D%20%20%2B%20%20%20%5Cfrac%7B1%7D%7Bx%7D%20)
... (2)
by substituting (1) into (2) to find x
![\frac{1}{z} + \frac{1}{4z} = \frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bz%7D%20%2B%20%20%5Cfrac%7B1%7D%7B4z%7D%20%20%3D%20%20%20%5Cfrac%7B1%7D%7B4%7D%20%20)
![\frac{5}{4z} = \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4z%7D%20%20%3D%20%20%20%5Cfrac%7B1%7D%7B4%7D%20%20)
\frac{5}{4z} = \frac{1}{4}
![\frac{4z}{5} = \frac{4}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B4z%7D%7B5%7D%20%20%3D%20%20%20%5Cfrac%7B4%7D%7B1%7D%20%20)
![\frac{4z}{1} = \frac{20}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B4z%7D%7B1%7D%20%20%3D%20%20%20%5Cfrac%7B20%7D%7B1%7D%20%20)
![z = \frac{20}{4}](https://tex.z-dn.net/?f=z%20%3D%20%20%20%5Cfrac%7B20%7D%7B4%7D%20%20)
⇒ z = 5
By substituting value of z into (1)
⇒ 4 (5) = x
⇒ x = 20
Thus the two numbers are 5 & 20
Answer:
y = 5x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here m = 5, hence
y = 5x + c
The line passes through the y- axis at (0, 3) ⇒ c = 3
y = 5x + 3 ← equation of line