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2 years ago

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he height after t seconds of an object projected upward with an initial velocity of 48 feet per second from a 210-foot tower can

be modeled by h=−16t^2 + 48t +210. The height of a neighboring 50-foot tall building is modeled by the equation h=50. Which statement best describes the validity of these solutions?

1 answer:

serious [3.7K]2 years ago

4 0

420 cheese balls in my souo

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Im so lost, please help me asap

almond37 [142]

Answer:

it's so simple ....

x + 141 = 135

x = 135 - 141

x = -6

it means ur answer is a

8 0

2 years ago

Need help asap please

cupoosta [38]

Answer:

c = 5

Step-by-step explanation:

IT'S THE THREE FOUR FIVE TRIANGLE!!

3^2 + 4^2 = c^2

√25 = c

c = 5

4 0

3 years ago

Read 2 more answers

A scalene triangle has sides measuring 200 feet, 107 feet, and 221 feet. What is the

jenyasd209 [6]

Answer:

P = 528

Step-by-step explanation:

P = a + b + c = 200 + 107 + 221 = 528

8 0

3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

2 years ago

Which expression represents the number

frozen [14]

Answer:

8 + i

Step-by-step explanation:

What you need to simplify this is the following "definitions" of i to different powers.

$i^1=i$

$i^2=-1$

$i^3=i^2*i=-1*i=-i$

$i^4=1$

Now we can sub these in for the various powers of i in our expression:

$6(1)+6(-i)-2(-1)+\sqrt{-1*49}$

Simplifying a bit:

$6-6i+2+\sqrt{i^2*49}$

Since we know that the square root of i-squared is i, and that the square root of 49 is 7, we can get rid of the radial sign as follows:

6 - 6i + 2 + 7i

And the final answer, in a + bi form, is

8 + i

7 0

3 years ago