I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
3% of 10%, that's .003 I'm pretty sure
Answer:
x>-1.5
Step-by-step explanation:
Answer:
x = -5 y = -9
Step-by-step explanation:
y = x -4
5x + y = - 34
substitute x-4 in for y to solve for x
5x + x - 4 = 34
solve for x . . . add 5x + x = 6x
so you now have 6x-4 = -34
add 4 to both sides of the equation
6x-4 + 4 = -34+ 4
6x = -30
divide both sides by 6
6x/6 = -30/6
x= -5
then you plug -5 for x in the first equation
y = x - 4
y= -5 -4
y =-9
x= -5 y= -9
