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2 years ago

How to use original price and markup to find retail price? Original price is $62 and %15 mark up.. What's the retail price?

Mathematics

2 answers:

PSYCHO15rus [73]2 years ago

7 0

Retail would be $71.30, grab the $62 and multiply it by 0.15 and it gives you the answer

Sonbull [250]2 years ago

6 0

Answer:

pretty sure its $72.94

Step-by-step explanation:

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PLEASE HELP! GEOMETRY.

vitfil [10]

I hope this helps you

3 0

3 years ago

For his long distance phone service, Keith pays a $3 monthly fee plus 11 cents per minute. Last month, Keith's long distance bil

Allushta [10]

The number of minutes for which Keith was billed = 97

Step-by-step explanation:

Step 1:

It is given that Keith pays a fixed fee of 3$ a month and 11 cents per minute for the number of minutes used.

Total cost = Fixed cost + Per minute cost

If x represents the number of minutes consumed in a month then we can compute the total cost using the below equation:

Total cost = 3$ + 0.11 * x

Step 2:

The total cost is 13.67$

Substituting in the equation we get

13.67 = 3 + 0.11 * x

x = 10.67 / 0.11 = 97 minutes

Step 3:

Answer:

The number of minutes for which Keith was billed = 97

3 0

3 years ago

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

6 0

3 years ago

The polynomial of degree 4, P ( x ) , has a root of multiplicity 2 at x = 1 and roots of multiplicity 1 at x = 0 and x = − 2 . I

ICE Princess25 [194]

We want to find a polynomial given that we know its roots and a point on the graph.

We will find the polynomial:

p(x) = (183/280)*(x - 1)*(x - 1)*(x + 2)*x

We know that for a polynomial with roots {x₁, x₂, ..., xₙ} and a leading coefficient a, we can write the polynomial equation as:

p(x) = a*(x - x₁)*(x - x₂)...*(x - xₙ)

Here we know that the roots are:

x = 1 (two times)
x = 0
x = -2

Then the roots are: {1, 1, 0, -2}

We can write the polynomial as:

p(x) = a*(x - 1)*(x - 1)(x - 0)*(x - (-2))

p(x) = a*(x - 1)*(x - 1)*(x + 2)*x

We also know that this polynomial goes through the point (5, 336).

This means that:

p(5) = 336

Then we can solve:

336 = a*(5 - 1)*(5 - 1)*(5 + 2)*5

336 = a*(4)*(4)*(7)*5

336 = a*560

366/560 = a = 183/280

Then the polynomial is:

p(x) = (183/280)*(x - 1)*(x - 1)*(x + 2)*x

If you want to learn more, you can read:

brainly.com/question/11536910

5 0

2 years ago

Find the distance between the following points: (0,0,0) and (-2,6,3)

marusya05 [52]

9514 1404 393

Answer:

3. 7

Step-by-step explanation:

The distance formula applies in 3 dimensions as well as 2.

d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

d = √((-2)² +6² +3²) = √(4 +36 +9) = √49

d = 7

The distance between the two points is 7 units.

6 0

2 years ago